An air cylinder is to be used to actuate the translational j

An air cylinder is to be used to actuate the translational joint of a robot manipulator. The piston diameter is 50 mm, the air pressure is 500 kPa (assumed constant), and the airflow rate is 0.01 m3/minute. Determine the following:

a) The force generated by the piston

b) The velocity during the forward stroke.

Solution

Piston Diameter = D = 50mm

Air flow rate = Q = 0.01 m³/minute = 0.01 * 10⁹ mm³/minute

Air pressure = P = 500 kPa = 500 x 10³ N/m² = 0.5 N/mm²

First calculate the area of piston A = pi()/4 * D² = 3.14/4 * 50² = 1962.5 mm²

a . So force generate by piston = F = P * A = 981.25 N

b. Piston velocity during forward stroke = V = Q/A = 0.01 * 10⁹/1962.5 = 5095.5 mm/min