can someone please help me with 3a and 3b c The product of a
can someone please help me with 3a and 3b?
Solution
3. a) & b)
For l = 2 i.e. even
a = (a1a2)
Thus, cycle is odd with 1=(2-1).
For l = 3 i.e. odd
a = (a1a3) (a1a2)
Thus, cycle is even with 2=(3-1).
For l=l+1,
a = (a1a(l+1)) (a1al) .... (a1a2)
Thus cycle is a product of l transportations.
Since, l+1 and l have opposite parity, for odd l, cycle of length l is even and for even l, cycle of length is odd.
