A shipment of 15 television sets contains 3 defective sets I

A shipment of 15 television sets contains 3 defective
sets. In how many ways can a hotel purchase
5 of these sets and receive at least 2 of the defective
sets?

Solution

X no of defective sets

p = 3/15 = 0.2

n =5

x is binomial with p = 0.2 and n =5

P(X>=2) = 0.26272