A tank of compressed O2 for flame curetting contains 20 kg O

A tank of compressed O_2 for flame curetting contains 20 kg O_2 at pressure 20 Mpa and temperature 30 degree C. What is the volume of the tank? V = nRT/P (Ideal gas law) {n = 3.125 moles/kg R = 0.082057 L. atm/mole degree K P = 197.38 atm.

Solution

Given Datas,

      P= 197.38 atm

n= 3.125 modes/kg

R=0.082057 L.atm/mole.K

T= 303 K

           

As per Ideal Gas Law

        

        V= nRT/P

            = (3.125 x 0.082057 x 303)/197.38

            = 0.393 Liter.

For 20 Kg,

     V= 20x0.393

      = 7.86 Liter

So volume of the Tank is 7860 cm3

Volume= pi x D2 /4 x H   where D is diameter and H is height of cylinder

Considering H=1 Meter = 100 cm

    pi x D2 /4 x H = 7860

 A tank of compressed O_2 for flame curetting contains 20 kg O_2 at pressure 20 Mpa and temperature 30 degree C. What is the volume of the tank? V = nRT/P (Idea

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