ignore answer on angel partSolution2 a total sample spaces n

ignore answer on angel part

2. a) total sample spaces n(s) = 6 x 6 = 36

let p(a) be the event of getting a sum of 7.

required sample space = {(1,6), (6,1), (2,5),(5,2), (3,4), (4,3)}

n(a) = 6

probabilty p(a) = n(a)/n(s) = 6/36 = 1/6

b) total sample spaces n(s) = 6 x 6 = 36

let p(a) be the event of getting same face up.

required sample space ={ (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}

n(a) = 6

probabilty p(a) = n(a)/n(s) = 6/36 = 1/6

c)total sample spaces n(s) = 6 x 6 = 36

let p(a) be the event of getting a sum of atmost 7.

required sample space = {(1,1) ,(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5)

(3,1),(3,2),(3,3),(3,4)

(4,1),(4,2),(4,3)

(5,1),(5,2)

(6,1)}

n(a) = 21

probabilty p(a) = n(a)/n(s) = 21/36 = 7/12

d)total sample spaces n(s) = 6 x 6 = 36

let p(a) be the event of getting a sum of atleast 9.

required sample space = {(3,6) , (4,5), (4,6), (5,4), (5,5), (5,6),(6,3),(6,4),(6,5),(6,6)}

probabilty p(a) = n(a)/n(s) = 10/36 = 5/18