R1 68 K ohm R2 10 ohm Find the TauR1 for Capacitor in serie

R1= 68 K ohm

R2 = 10 ohm

Find the Tau_R1, for Capacitor in series with R1 & the Tau_R2, for Capacitor in series with R2 What effect does larger resistor have on the charging and discharging of the Capacitor and why does it have this effect? The circuit hooked up the scope is essential the circuit below

Solution

R1eq= 68*1000/1068 kilo ohm

= 68000/1068 kilo ohm

= 63.67Kilo ohm

Ceq= (24+12)pF ( Capacitors are in parallel)

Tau R1= Req * Ceq = (63.67* 10^3) ( 36* 10^-12)

= 2.292 micro seconds

R2eq= (10*1000)/ (10+1000) = 9.9 Kilo ohm

Tau2= R2eq * Ceq =   (9.99* 10^3) ( 36* 10^-12)

=   0.356 micro seconds

Charging time depends on RC Cofficient Tau R1 is higher than Tau R2 so Circuit with R1 have larger charging and discharging time.