Assume that you have four hosts in an Ethernet segment These

Assume that you have four hosts in an Ethernet segment. These hosts have their IP addresses as shown below and those addresses are fixed (they cannot be changed). Find 1 subnet mask these hosts can possibly use such that they can be considered in the same subnet. Please indicate explain your solution. Host1: 145.122.146.25, Host2:145.122.95.137, Host3: 145.122.42.9, Host4:145.122.48.56

Solution

IP address was an address used in order to uniquely identify a device on an IP network. The address is made up of 32 binary bits, which can be divisible into a network portion and also the host portion with the use help of a subnet mask. The 32 binary bits are broken into four octets (1 octet = 8 bits). Each octet is converted to decimal and separated by a period (dot). For this reason only, an IP address is said to be expressed in dotted decimal format (for example, 145.122.146.25). The value in each octet ranges from 0 to 255 decimal, or 00000000 - 11111111 binary.

Here was how binary octets converted to decimal: The right most bit, or least significant bit, of an octet holds a value of 2⁰. The bit just to the left of that holds a value of 2¹. This continues until the left most bit, or most significant bit, which holds the value of 2⁷. So if all binary bits are a one, the decimal equivalent would be 255 as shown here:

Here was a sample octet conversion when not all of the bits are set to 1.

here the given ip address is 145.122.146.25

this ip address is in host1.first we find the subnet mask as the 122 is convert in binary 11110100

122=11110100

now find the subnet mask as the using formula

128 64 32 16 8 4 2 1

1 1 1 1 0 1 0 0

128+64+32+16+0+4+0+0=244

find to the all adresses

145 binary is 10010001

128+0+0+16+0+0+0+1=145

146 binary is 10010010

128+0+0+16+0+0+2+0=146

25 binary is 11001

128+64+0+0+8+0+0+0=200

the given ip address is 145.122.146.25

the subnet mask is 145.244.146.200