Q5 In a study conducted by some Statistics students 66 peopl

Q5 In a study conducted by some Statistics? students, 66 people were randomly assigned to listen to rap? music, music by? Mozart, or no music while attempting to memorize objects pictured on a page. They were then asked to list all the objects they could remember. The summary statistics for each group are shown in the table. Complete parts a and b.

Again and Again PLEASE DON\'t ANSWER IF YOU ARE NOT SURE 100%

Solution

(a):Ho:_m-_r=0 against H1:_m-_r<0( left-tail test). At 5% level of significance, the table value of Z(large sample) is -1.645. Then Zcal=(x_mbar-x_rbar)/[[(²1/n1)+(²2/n2)]=(9.07-9.69)/[(7.5076/20)+(15.5236/26)]=-0.62/0.9861=-0.6287.

So Zcal>Ztab, so we reject Ho. Therefore, we accept H1:_m-_r<0 , i.e., there is a evidence that the mean number of objects remembered by those who listen to mozart is less than the mean number of objects remembered by those who listen to rap music.

(b):Ho:_m-_nomus=0 against H1:_m-_nomus<0( left-tail test). At 10% level of significance, the table value of Z(large sample) is -1.28.

Then the 90% confidence interval for the group that listen to mozart and group that belong to no music is [x_mbar-x_nomusbar)+-(-1.28)[[(²1/n1)+(²2/n2)]]]=[(9.07-12.02)+-[(-1.28)*(1.1743)]]=[-2.95-+1.5031]=(-4.4531,-1.4469).

With 90% confidence , that the mean number of objects remembered by those who listen to mozart is less than the mean number of objects remembered by those who listen to no music.