How many bits are needed to represent all the uppercase and

How many bits are needed to represent all the uppercase and lowercase characters of the alphabet, the digits 0 through 9, and an additional 20 symbols?

Solution

No of Alphabets both upper case and lower case =2*26 =48

no of bits required for 48 is = 6 bits

for 0,1 = 2bits

for 2 = 2bits

for 3 = 2 bits

for 4= 3 bits

for 5 = 3 bits

for 6 = 3 bits

for 7 = 3 bits

for 8 = 4 bits

for 9 = 4 bits

no of bits require for 0 to 9 is 26

and 20 symbols take 5 bits

Total bits for this problem is 6+26+5= 37