the quadratic model for the sequence is a03 a2 a636 the quad
the quadratic model for the sequence is a0=3 a2= a6=36
 the quadratic model for the sequence is a0=3 a2= a6=36
 the quadratic model for the sequence is a0=3 a2= a6=36
Solution
assuming that a2=0
f(A) = lA^2 + mA + n
 
 When A0=3 So n = 3.
 
 So we know now
 
 f(A) = lA^2 + mA + 3
 
 A2=0 so 4l + 2m + 3 = 0 eqn(1)
 A6=36 so 36l + 6m + 3 = 36 eqn(2)
 
 multiply eqn(1) by 3 and subtract from eqn(2):
 
 so 24l - 6 = 36 ie l = 7/4 substitute this back in eqn(1):
 
 7 + 2m + 3 = 0 hence m = -5
 
 So quadratic model is
 
 f(A) = (7/4)A^2 - 5A + 3

