This speed governor has initial velocity VA VB 25 ms and R

This speed governor has initial velocity V_A = V_B = 25 m/s and R = 120 mm A M_y = 500 N-mm is then applied for 7 sec and R structures to 160 mm Calculate V_A and V_B final Note that V_A and V_B are velocities.

Solution

solution:

1) it is inertia governor and it is use to govern the speed of rotating shaft

2) here moment of system would be I=2mk2

where m=.6 kg,k=.12 m

hence I=2*.6*.12*.12=.01728 kg-m2

3) when torque applied tosystem then it will create accelaration in system hence accelaration of system is as follows

T=My=I *a

a=accelaration=My/I=.5/.01728=28.935 rad/sec2

4) hence final angular velocity is

w=w0+a*time

where w0=Va/r=25/.12=208.33 rad/sec and time =t=7 sec

hence w=208.33+7*28.935=410.87 rad/sec

this is final angular velocity of masses

5)final tangential velocity of masses A andB are

Va=Vb=w/R

R=.16 m

Va=Vb=410.87/.16=65.74 m/s2