Two points A and B are on opposite sides of a building A sur

Two points A and B are on opposite sides of a building. A surveyor selects a third point C to place a transit. Point C is 49 feet from point A and 63 feet from point B. The angle ACB is 49°.

How far apart are points A and B?

Solution

We have to use law of cosine here

AB²= AC²+AB² -2 AC AB cos <ACB

AB²=49²+63²-2(49)(63)cos 49

AB²=6370-6174 cos 49

AB= 48.16feet

Distance between A and B is 48.16 feet