What is the total charge of all protons in 1 gram of water H

What is the total charge of all protons in 1 gram of water (H2O)?

Solution

Number of protons for a single molecule of water :

2 protons - two hydrogen atoms

8 protons - one oxygen atom

i.e., totally 10 protons in single molecule of water.

mass of water m = 1 g

Molecular mass of water M = 18 g

Number of moles n = m/M

                            = 1/ 18

We know 1 mole contain 6.023 x10 ²³ molecules

So, number of molecules in n moles N = n(6.023 x10 ²³ )

                                                        = (1/18)(6.023 x10 ²³ )

                                                        = 3.346 x10 ²² molecules

Total number of proton in 1 g of water N \' = 10 N    Since each molecule have 10 protons

                                                           = 3.346 x10 ²³ protons

Charge of N \' protons Q = N \' e

Where e = charge of proton = 1.6 x10 ^-19 C

Substitute values you get , Q = (3.346 x10 ²³x1.6 x10 ^-19 )

                                           = 53.537 x10 ³ C