Juan left home on his bicycle at 1000am traveling at 21kmh A

Juan left home on his bicycle at 10:00a.m. traveling at 21km/h. At noon, his brother set out after him on his motorcycle following the same route. If the motorcycle traveled at 63km/h, what time did Juan\'s brother overtake him?

Solution

You will need to apply the \"distance\" formula:
d = rt
where
d is distance
r is rate or speed
t is time
.
Let x = amount of time Juan\'s brother took to overtake him
.
x+2 = time Juan was on his bicycle
.
\"distance traveled by Juan\" = \"distance traveled by Juan\'s brother\"
.
21(x+2) = 63x
21x + 42 = 63x
42 = 42x
1 hour = x
.
Therefore, Juan\'s brother overtook him 1 hour after starting. And, since he started at noon, Juan\'s brother will overtake him at 1 PM.
.
Answer: 1 PM