1 A researcher compares the frequency of participants who sl

1. A researcher compares the frequency of participants who sleep primarily on their stomach, back, or side during the night. What is the critical value for a chi-square goodness-of-fit test at a .05 level of significance?

a. 2

b. 3

c. 3.84

d. 5.99

2. To compute the expected frequencies for a chi-square test for independence, we use which of the following formulas?

a. k - 1

b. p(n)

c. (row total + column total)/grand total

d. (row total x column total)/grand total

3. A researcher computes a 2 x 2 chi-square test for independence. What is the critical value for this test at a .05 level of significance?

a. 3.84

b. 5.99

c. 7.81

d. 9.49

4. One way a researcher can correct for having expected frequencies smaller than five is to increase the levels of the categorical variable such that the number of levels

a. is equal to the sample size

b. is greater than four

c. is less than five

d. is minimal

5. A researcher reports the following results for a chi-square test: x²(1) = 5.386, p < .05 (V = 0.224). If this test were a test for independence, then how many groups were observed?

a. 1

b. 2

c. 3

d. 4

6. A researcher conducts a chi-square goodness-of-fit test in which k = 3 and x²= 4.32. What is the decision for this test at a .05 level of significance?

a. Retain the null hypothesis.

b. Reject the null hypothesis.

c. There is not enough information to answer this question.

7. Which of the following is an example of a parametric test?

a. analysis of variance

b. one-sample t-test

c. Pearson correlation

d. all of the above

8. When computing a chi-square goodness-of-fit test, the frequency expected in a given cell should never be less than

a. the sample size

b. the number of cells

c. the frequency observed

d. five

9. What is the key assumption for a chi-square goodness-of-fit test?

a. The population is normally distributed.

b. Observed frequencies are independently recorded in each cell.

c. Expected frequencies are homogeneous.

d. all of the above

Solution

The critical value for a chi-square goodness-of-fit test at a .05 level of significance is c. 3.84.

To compute the expected frequencies for a chi-square test for independence, we use d. (row total x column total)/grand total

3.The degress of freedom is (2-1)*(2-1)=1

Thus the critical value for this test at a .05 level of significance is a. 3.84.

5. A researcher reports the following results for a chi-square test: x²(1) = 5.386, p < .05 (V = 0.224). If this test were a test for independence, then 2 groups were observed.

b. one-sample t-test is an example of a parametric test.