Two small planes start from the same point and fly in opposi

Two small planes start from the same point and fly in opposite directions. The first plane is flying 25 mph slower than the second plane. In 2 hrs, the planes are 470 mi apart. Find the rate of each plane.

Solution

Let x = rate of the slower plane (First plane!)
x+25 = rate of the faster plane (Second plane!)

The planes fly for 2 hours, where Distance = R*T
Distance between the planes = SUM of the distances.
R*T + R*T= 470 miles
2*x + 2*(x+25)=470
2x+2x + 50 = 470
4x+50=470
4x=420
x=105 mph First plane
x+25= 105+25=130 mph Second plane.