Using C Ask the user for a base float and a positive exponen

Using C++:

Ask the user for a base (float) and a positive exponent (int). Calculate the base raised to the power of the exponent using a loop. For example:

Use the following format specifiers to get the precision to match the answers:

Solution

Power.cpp

#include <iostream>
#include <iomanip>

using namespace std;

int main()
{
float b;
int e;
cout << \"Please enter the base: \";
cin >> b;
cout<<\"Please enter the exponent: \";
cin >> e;
cout.setf(ios::fixed, ios::floatfield);
cout.precision(2);
float result=1;
for(int i=0; i<e; i++){
result = result * b;
}
cout<<\"The answer is \"<<result<<endl;
return 0;
}

Output:

sh-4.3$ g++ -std=c++11 -o main *.cpp                                                                                                                                                                                            

sh-4.3$ main                                                                                                                                                                                                                    

Please enter the base: 2                                                                                                                                                                                                        

Please enter the exponent: 3                                                                                                                                                                                                    

The answer is 8.00                                                                                                                                                                                                              

sh-4.3$