Explain the answers in sufficient details ie show the work a
Solution
a) Let we have two regions, Region1 and Region2.
It is given that 60% nucleotides in 1st region is A&T (30% each) and remaining 40% is of G&C nucleotides(20% each). Probability of the nucleotides in Region1:
Similarly for region2, Probability of the nucleotides in Region2:
Probability of getting both are same nucleiods, we must multiply the individual probabilities.
Probability of getting both has type A nucleoids=P(A1)*P(A2)
Probability of getting both has type T nucleoids=P(T1)*P(T2)
Probability of getting both has type G nucleoids=P(G1)*P(G2)
Probability of getting both has type C nucleoids=P(C1)*P(C2)
Required probability=P(A1)*P(A2)+ P(T1)*P(T2)+ P(G1)*P(G2)+ P(C1)*P(C2)
=0.25
b)
It is given that two regions are independent. To find probability to select three nucleoids sequence (triplets) from each of the two regions are same.
All combinations made with the nucleoids A, T, G and C taking three at a time 4C3.
The number of all combinations of 4 things taken 3 at a time is 4C3=4
Possible selections are ATG, TGC, GCA and CAT
Suppose we get outcome as ATG from Region1, so Probability of getting it is
| Nucleotides | P (N) |
| A1 | 0.2 |
| T1 | 0.2 |
| G1 | 0.3 |
| C1 | 0.3 |
