Researchers find that in of a sample of 2460 moths 1254 have

Researchers find that in of a sample of 2460 moths, 1254 have a dominant phenotype. Assuming a very good fit to the H-W model for two alleles of one gene, estimate the genotype frequencies of the moths.

Solution

(p + q)² = p² + 2pq + q² = 1.

The realistic solution of this equation is q = 1 p.

where q is the genotype frequency of reccesive allele and p is the genotype frequency of dominant allele

total no. of moths = 2460

dominant phenotype= 1254

hence reccesive phenotype=2460-1254

= 1206

q² = 1206/2460

=0.49 (genotype frequency of recessive genotype)

q= 0.7

formula is p+q=1

p=1-q

p=1-0.7

p= 0.3

frequency of heterogygote

=2pq

=2*0.7*0.3

=0.42

and frequency of dominant genotype is p²=(0.3)²

=0.09