A die is rolled until an ace 1 shows What is the probability

A die is rolled until an ace (1) shows. What is the probability that an ace will show on the fourth try?1. A die is rolled until an ace (1) shows. What is the probability that an ace will show on the fourth try?

Solution

A dice is a solid cube, having 6 faces that is ={1,2,3,4,5,6} respectively..

A pack of cards has 52 cards

It has 13 cards of each suit,that is Spades,Clubs,Hearts and Diamonds.

In these cards spades and clubs are black cards

and the another is hearts and diamonds are redcards

There are 4 honours of each suit.

These are Aces,kings,Queens and Jacks.

Aces=4cards,Kings=4,Queens=4 and Jacks=4.

So if a die is thrown,the possibilites is ={1,2,3,4,5,6} = 6^1

The probability than an ace will show on fourth try = {4c1+4c2+4c3+4c4}=15

p(E)=total possibilities of ace /total no.of dice is thrown

p(E)={4c1+4c2+4c3+4c4}/6^1

=15/6

=5/2

1) probability than an ace will show on fourth try=4c4

one die is thrown = 6^1

probability of an ace will show on fourth try is P(E) =4c4/6^1

=1/6