Homework Sourseon the moonthe acceleration due to gravity is 16 msec2 If th
on the moon,the acceleration due to gravity is 1.6 m/sec^2. If the rock is dropped into a deep crevasse, how fast will it be going just before it hits the bottom? How deep is the crevasse if it took exactly 1 seconds to hit the bottom? Please use a(t) for accleration, v(t) for velocity,and s(t) to find the answer.
Please show your work. thank you
Please show your work. thank you
Solution
we have s(t)= 1/2gt^2 =>s = 0.5*1.6*1 = 0.8 m deep we have v(t)=u+at =>v = 1.6*1 = 1.6 m/s is the speed before it hits the bottom
