A 75 degree F a can of cold soda gains 09 kJ of heat as it w
Solution
>> Let T1 is the initial temperature = 75°F = 23.889°C
>> Now, energy released = 0.9KJ/°C
>> To find energy released in KJ/°F, let\'s find out total energy released for a certain change in temperature
and, then by changing that temperature from °C to °F, and having total energy released,
We can easily find out the energy released per °F
>> Let, T2 = 28.889°C
>> So, Temperature increase = T2 - T1 = 28.889 - 23.889 = 5°C
>> As, energy released per °C = 0.9 KJ
=> Total energy released now = 0.9*5 = 4.5 KJ
>> Now, using Temperature in °F,
As, T1 = 23.889°C = 75°F
and, T2 = 28.889°C = 84°F
>> So, increase in Temperature in °F = 84 - 75 = 9°F
and, as total energy released = 4.5 KJ
>> So, Energy released per °F = Total Energy Released /Increase in Temperature in °F = 4.5/9 = 0.5
=> Energy rleaseed per °F = 0.5 KJ/°F .....ANSWER.....OPTION (B)....
