A particle is moving along a projectile path where the initi

A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second. What is the maximum height of the particle? 100 feet 96 feet 60 feet 56 feet =-16 t^2+16(t)+94

Solution

Applying one of linear motion equation:

v^2 = u^2 - 2gS

where v is the final velocity ; u = intial velocity ; g = acc. due to gravity ; S = height travelled

At max height velocity = 0 i .e. v =0 ; intial velocity u = 16 ft/sec ; g = 32 ft/sec^2

0 = u^2 -2gS

S = u^2/2g = 16^2/2*32 = 4 feet

So, maximum height = intial height + height travelled = 96 +4 = 100 feet