PotsRUs obtains its stock of outdoor decorative pots from th
Solution
Let X1, X2 & X3 be the number of pots bought in a quarter from supplier 1, 2 and 3 respectively.
Thus, X1, X2, X3 <= 140
For meeting the quarterly demands, equation for no. of large pots is given by:
0.35*X1 + 0.3*X2 + 0.1*X3 >= 100
For Medium pots:
0.4*X1 + 0.25*X2 + 0.1*X3 >= 60
For Small Pots:
0.15*X1 + 0.35*X2 + 0.5*X3 >=50
For tiny pots:
0.1*X1 + 0.1*X2 + 0.3*X3 >= 40
Also, the total cost of pots in a quarter is given by,
Z = 4*X1 + 3*X2 + 2*X3
So, the LP problem is given as below:
Minimize Z = 4*X1 + 3*X2 + 2*X3
Constraints:
0.35*X1 + 0.3*X2 + 0.1*X3 >= 100
0.4*X1 + 0.25*X2 + 0.1*X3 >= 60
0.15*X1 + 0.35*X2 + 0.5*X3 >=50
0.1*X1 + 0.1*X2 + 0.3*X3 >= 40
X1, X2, X3 <= 140
and X1, X2, X3 >= 0
By solving the above LP problem, we get
Z = 1160
X1 = 140, X2 = 140 & X3 = 90
Thus, 140 no. of pots from supplier 1, 140 no. of pots from supplier 2 and 90 of pots from supplier 3 to be bought to meet the quarterly demand with minimum cost of 1160.

