Homework SourseWrite a program to solve the date and days passed in a year
Solution
Answer:
//include header files
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
//declare arrays for months
int a[12]={31,28,31,30,31,30,31,31,30,31,30,31};
//for leap-year
int b[12]={31,29,31,30,31,30,31,31,30,31,30,31};
//check leap-year
int checkleapYear(int y)
{
//Condition for a leap-year
if(((y%4==0) ||(y%400==0)) &&(y%100!=0))
//return 1
return 1;
//return o if not a leap-year
return 0;
}
//Calculate the total days
void findDays(int m, int d, int y)
{
//Check leap year
int c=checkleapYear(y);
int tdays=0;
//For leap-year
if(c==1)
{
//Calculate days
for(int kk=0;kk<m-1;kk++)
{
//Add days
tdays+=b[kk];
}
}
//for non-leap-year
else
{
//calculate days
for(int kk=0;kk<m-1;kk++)
{
//Add days
tdays+=a[kk];
}
}
//Add d
tdays=tdays+d;
//print total days
printf(\"\ There are %d days passed in the year %d\", tdays, y);
}
//method find date
void findDate(int tdays, int y)
{
//Declare m
int m=0;
//Check for leap-year
int c=checkleapYear(y);
int kk=0;
//For leap-year
if(c==1)
{
//Find month
while(tdays>b[kk])
{
//Imcremnt month
m=m+1;
//Reduce days
tdays=tdays-b[kk];
//Move to the next value
kk++;
}
}
//For non-leap-year
else
{
//Find month
while(tdays>a[kk])
{
//Increment the month
m=m+1;
//Reduce days
tdays=tdays-a[kk];
//Move to the next value
kk++;
}
}
//Increment month
m+=1;
//print date
printf(\"\ The date is %d-%d-%d\", m,tdays,y);
}
//main
int main()
{
//Declare c
int c;
char c1,c2=\'N\';
int tdays, d,m,y;
//Inifinite-loop
do
{
//display program infor
printf(\"\ This program will find days passed or date in the year\");
printf(\"\ \\t 1) Input date(mm/dd/yyyy) to find days passed\");
printf(\"\ \\t 2) Input passed days to find date in the year\");
printf(\"\ Your choice (1/2):\");
scanf(\"%d\", &c);
switch(c)
{
//find days passed
case 1:
//get date
printf(\"\ Please input data (mm-dd-yy):\");
scanf(\"%d%c%d%c%d\", &m, &c1, &d, &c1, &y);
//Call findDays()
findDays(m,d,y);
break;
//Find date
case 2:
//Get total-days
printf(\"\ Input days:\");
scanf(\"%d\", &tdays);
//Get year
printf(\"\ Years:\");
scanf(\"%d\", &y);
//Call findDate()
findDate(tdays, y);
break;
//Default
default:
printf(\"INVALID\");
}
//Get user choice for repitition
printf(\"\ Do more (Y/N) ?\");
scanf(\"%c\", &c2);
scanf(\"%c\", &c2);
}while(c2!=\'N\');
return 0;
}
sample output:
sh-4.3$ gcc -o main *.c
sh-4.3$ main
This program will find days passed or date in the year
1) Input date(mm/dd/yyyy) to find days passed
2) Input passed days to find date in the year
Your choice (1/2):1
Please input data (mm-dd-yy):12-31-1981
There are 365 days passed in the year 1981
Do more (Y/N) ?Y
This program will find days passed or date in the year
1) Input date(mm/dd/yyyy) to find days passed
2) Input passed days to find date in the year
Your choice (1/2):2
Input days:78
Years:1981
The date is 3-19-1981
Do more (Y/N) ?N
sh-4.3$
