The load profile shown in Table A must be supplied using the

The load profile shown in Table A must be supplied using the units whose characteristics are summarised in Table B a) Table C summarises three solutions to this problem. Check the feasibility of each of these solutions. If a solution is infeasible, indicate all the constraints that are not satisfied. Assume that 60 MW of reserve must be carried at all times. b) Using the cost curves of these units shown on the figure below, calculate the total cost of all the feasible solutions. Table A Hour Load 400 500 600400 TableB UnitMi Un Minimum umMin Up Min DownSt Initial Status Down for 6 hours Down for 1 hour Up for 6 hours Up for 12 hours Maxim MW 100 tart-up Cost [$] Time Time 25 50 150 200 150 250 400 200 600 800

Solution

None of the solutions provided table C are feasible. Here are the reasons: Let us consider solution 1 ( S1 ). In this solution, the MW of power provided in hour 1 is 350 ( 100 MW + 250MW ) only, while the requirement is

400MW. Now, in case of solution 2 ( S2), although by addign each of the MW in each hour, we are getting the required MW as mentioned in table A ( i.e, 150+250=400 which is same as the hour 1 requirement of table A, 250+250=500MW which is same as the requirement of hour 2 of table A, 100+250+250=600MW which is same as the requirement of hour 3 of table A, 200+200=400 which is same as the requirement of hour 4 of table A ), but C cannot be up for more than 3 hours at a stretech. However the table is indicating C is running for all the 4 hours. Hence this solution is also not feasible,\'

Now consider solution S3. In this case, the power drawn from unit B is 40 in hour 3 which is less than its minimum capacity. Again, power drawn from unit C in hour 3 is less than its minimum capacity which 150MW. Hence this solution is also not feasible.

Since none of the mentioned solutions are feasible, it is not possible to calculate the cost.