QUESTION 1 Students scores are averaging 85 with a standard

QUESTION 1

Students’ scores are averaging 85 with a standard deviation of 4. The 96% will have a value close to:

60

70

85

93

6 points   

QUESTION 2

When a sampling distribution of Xbar should be considered?

Path: p

Words:4

6 points   

QUESTION 3

If the number of calories on a slice of   strawberry pie is in average 160 with a standard deviation of 10 then the probability of having a slice of apple pie with more than 180 calories is the closest to:

  

80%

40%

4%

-15%

6 points   

QUESTION 4

The X value range is:

-1% to +1%

-infinite to +infinite

-100 to +100

0 to 1

4 points   

QUESTION 5

The expected value of a discrete random variable is:

n*p*q

x*p(x)

(x - µx)2 p(x)

p(x)  

4 points   

QUESTION 6

When one is using the standard normal distribution, P(Z < 0) is:

-.5

1

-

50%

4 points   

QUESTION 7

In few lines explain what z-scores are and why they are useful?

Path: p

Words:0

4 points   

QUESTION 8

as the sample size gets larger, the standard deviation of the sample mean also gets larger and larger.

True

False

4 points   

QUESTION 9

A standard normal distribution has a standard deviation of ____and a mean of ____

zero, zero

zero, one

one, zero

one, one

4 points   

QUESTION 10

Which of the following is a valid probability value for a discrete random variable?

101%

99.999%

1.35

-2.63%

4 points   

QUESTION 11

A student\'s grade on an examination was transformed to a z value which is negative. Therefore, we know that he scored

higher than 16% of the class

lower than at least 45% of the class

higher than 45% of the class

above the mean but below the median

above the 3rd quartile

6 points   

QUESTION 12

In a large automobile manufacturing company, the mean life of hybrid motors is normally distributed with a mean of 100,000 miles and a standard deviation of 10,000 miles. If a random sample of 144 motors is selected, what is the probability that the sample mean will be below 99,000 miles per year is close to:

-10%

35%

50%

11%

6 points   

QUESTION 13

What is the expected value of a lottery ticket where there are only 1 chance in 10 millions of winning the grand prize of $5 Million, and 100,000 in 10 millions chances of winning $100?

Give a brief explanation.

Path: p

Words:0

6 points   

QUESTION 14

The area under the normal curve between z = -2 and z = -3 is _______than the area under the normal curve between z = 3 and z = 4.

equal to

less than

greater than

A, B, or C above depending on the value of the mean

6 points   

QUESTION 15

The customers spent in average $80 with a standard deviation of $5.
The probability of a customer to spend $80 or more is _____________

-48%

85

50%

100%

6 points   

QUESTION 16

The earnings set of data has an average of $75 with a standard deviation of $5. The probability of having more than $60 is closer to:
NOTE: if you understand the concept you don\'t really need to do any computation.

35%

99%

50%

60%

4 points   

QUESTION 17

The total area under a normal distribution is = 1

True

False

4 points   

QUESTION 18

If the X + 2*s.d. from the mean, the area under the curve (relative to the mean) is close to:

.9500

1.96

.2000

.4800

increases, exponential

6 points   

QUESTION 19

If the sampled population has mean 48 and standard deviation 16, then the mean and the standard deviation for the sampling distribution of Xbar for n = 16 are

48 and 4

48 and 1

12 and 4

48 and 16

4 and 1

6 points   

QUESTION 20

If the mean value is 20 with a stdev of 1. The best approximation for the low 15% will be:

18

15

22

20

60

70

85

93

Solution

Q1.
P ( Z < x ) = 0.96
Value of z to the cumulative probability of 0.96 from normal table is 1.751
P( x-u/s.d < x - 85/4 ) = 0.96
That is, ( x - 85/4 ) = 1.75
--> x = 1.75 * 4 + 85 = 92.004   ~ 93

Q3.
P(X > 180) = (180-160)/10
= 20/10 = 2
= P ( Z >2) From Standard Normal Table
= 0.0228 ~ 4  

Q20.

P ( Z < x ) = 0.15
Value of z to the cumulative probability of 0.15 from normal table is -1.036
P( x-u/s.d < x - 20/1 ) = 0.15
That is, ( x - 20/1 ) = -1.04
--> x = -1.04 * 1 + 20 = 18.964 ~ 18   
              
              

QUESTION 1 Students’ scores are averaging 85 with a standard deviation of 4. The 96% will have a value close to: 60 70 85 93 6 points QUESTION 2 When a sampling
QUESTION 1 Students’ scores are averaging 85 with a standard deviation of 4. The 96% will have a value close to: 60 70 85 93 6 points QUESTION 2 When a sampling
QUESTION 1 Students’ scores are averaging 85 with a standard deviation of 4. The 96% will have a value close to: 60 70 85 93 6 points QUESTION 2 When a sampling
QUESTION 1 Students’ scores are averaging 85 with a standard deviation of 4. The 96% will have a value close to: 60 70 85 93 6 points QUESTION 2 When a sampling
QUESTION 1 Students’ scores are averaging 85 with a standard deviation of 4. The 96% will have a value close to: 60 70 85 93 6 points QUESTION 2 When a sampling

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