2x1ln21x dx i think its integration by parts but i cant seem

(2x-1)*ln(21x) dx

i think its integration by parts but i cant seem to set it up right
might not be

u=ln(21x) du=21/21x = 1/x
v\'=2x-1 v=x²-x
int = ln(21x)*(x²-x) - (x²-x)/x dx

= ln(21x)*(x2-x) - x-1 dx

= ln(21x)*(x²-x) - x²/2 + x + C

$(2x-1)*ln(21x) dx i think its integration by parts but i cant seem to set it up right might not beSolutionu=ln(21x) du=21/21x = 1/x v\'=2x-1 v=x2-x int = ln(21x$

2x1ln21x dx i think its integration by parts but i cant seem

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