By determining the water potential of a potato tissue by usi

By determining the water potential of a potato tissue by using the Chardakov method and analyzing the change in mass. Will the experimental values be the same as they would be found in a healthy, growing, living potato? Why or why not?

Solution

Basic rule for Chardakov experiment: The Chardokov method provides a quick means to determine plant tissue water potentials. This method depends on the change in density in a solution that occurs after a tissue has been immersed in it. The solution gains or looses water depending on the water potential of the tissue. If the density of a solution does not change (no net movement of water) then this solution has the same water potential as the tissues that were incubated in it. It is assumed that solute movement between tissue and solution is negligible. Density changes can be observed by watching whether a drop of the original solution floats or sinks in the test solution after tissue incubation. Alternately, for a more accurate measurement of changes in the solution density, a refractometer can be used.

The experiment value should not be remain same for healthy,growing & living potato because every ojbect has different value of water contain in it. If the newly healthy potato has high level of water in it than it will not absorbed water so it will not exchange any mass. So mass value will not remain same.

Hope you get your answer...

Thanks & Regards :-)