Solve the triangle using either law of sines or law of cosin

Solve the triangle using either law of sines or law of cosines.

Solution

using cosine law

a²=b²+c²-2bc cos A

a²= 10²+8²-2(10)(8)cos 46

a²= 164- 160 cos 46

a= 7.3

using sine law

sinA/a= sinB/b

sin 46/7.3= sinB/10

SInB= 10 sin 46/7.3

B= 80.2degree

C=180-A-B= 53.8 degree