Find tancos123 and sinsec1xSolutionSolution We know that co

Find tan(cos^-1(2/3)) and sin(sec^-1(x))

Solution

Solution :

We know that cos^{-1}x= tan{-1}((1-x^2)/x)

Thus cos^-1 (2/3) = tan^-1(5/3/2/3)

=tan ^-1 (5/2)

Therefore tan (cos^-1(2/3)=tan(tan^-1(5/2)

=5/2. Ans.

sin ( sec^-1(x) = sin(cos^-1(1/x)

sin(sin^-1(1-1/x^2))

=(x^2-1)/x. Ans

 Find tan(cos^-1(2/3)) and sin(sec^-1(x))SolutionSolution : We know that cos^{-1}x= tan{-1}((1-x^2)/x) Thus cos^-1 (2/3) = tan^-1(5/3/2/3) =tan ^-1 (5/2) Theref

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