Write the equation of a line through the given point and per

Write the equation of a line through the given point, and perpendicular to the given line. Write the final answer in slope intercept form.

1. (-4,-3) ; y=2/5x-2

2. (2,6) ; y +3 = -3/7 (x-2)

If you are given a line :y=mx+c. Then slope of a line perpendicular to it is: -1/m

Slope of given line is: 2/5

Hence slope of line perpendicular to it is: -5/2

In slope intercept form equation is: y=-5/2x+c

Substituting the given point we get:

-3=(-4)*(-5/2)+c

This gives :c=-13

Hence equation is: y=-5/2x-13

Slope of given line is: -3/7 hence slope of line perpendicular to given line is: 7/3

Equation in slope intercept form is: y=7/3x+c

Substituting given point gives:

6=(7/3)*2+c

Solving gives:c=4/3

Hence equation is: y=7/3x+4/3