A flexible pavement was designed for the following traffic w
Solution
Solution:
D1 = 4 inch of HMA; a1= 0.44
D2 = 4 inch HMA; a2 = 0.40
D3 = 8 inch crushed stone; a3 = 0.11
Reliability = 70%
So = 0.5 PSI = 2
TSI = 2.5 M1 = M2 = M3 = 1
Calculations:
SN = a1D1 + a2D2M2 + a3D3M3 ------------ (1)
Equation (1) gives:
SN = 4.24
Axle Loads ---------
Single 8-kips = 0.03932
Tandem 15-kips = 0.04308
Single 40-kips = 22.164
Tandem 40-kips = 2.042
Calculating 18-kip ESALs:
Daily W18 = 1300(0.03932) + 900(0.04308) + 20(22.164) + 200(2.042) = 941.568
So;
Total W18 = 941.568 x 365 x 12
= 4124067.84
Zr = -0.524
Now, from design equation of AASHTO
Mr = 5250.31 psi
