2 Mass of dry NaCl 3 Massmass percent show work 4 Massvolume

2. Mass of dry NaCl

3. Mass/mass percent (show work)

4. Mass/volume percent (show work)

5. Moles of dry NaCl (show work)

   (molar mass of NaCl is 58.54 g/mol)

6. Volume of solution in liters

7. Molarity of NaCl solution (show work)

Solution

1)

54.129 g - 42.889 g = 11,240 g of solution

2)

44,079 g - 42.889 g = 1,190 grams of dy salt

3)

%m/m= (1,190g salt/11,240g solution)*100= 10,59%
The density of 10%m/m solution of salt is aprox. 1,08g/mL
therefore
11,240g solution*(1mL/1,08g)= 10,407 mL

4)
%m/v= (1,190g salt/ 10,407mL)*100= 11,43%

5)
moles of salt=
1,190g NaCl*(1mol NaCl/58,54g NaCl)= 2,036x10^-2 moles NaCl

6)

volume:
10,407 mL*(1liter/1000mL)= 1,0407x10^-2 L

7)

M= moles of salt/liters of solution
M = 2,036x10^-2 moles NaCl/1,0407x10^-2 L= 1,956 M