Consider the reaction Bs32O2gB2O3s H 1270kJ What will H be f

Consider the reaction

B(s)+32O2(g)B2O3(s), H =1270kJ

What will H be for the reaction if it is reversed?

H Changes sign when a proceSs is reversed

Solution

given

B (s) + 3/2 O2 (g) --> B2O3 (s) ===> dH = -1270 kJ

now

when the reaction is reversed

the value of dH will remain , only the sign will change

so

for the reverse reaction , dH = 1270 kJ