Mr Clark needs new tires for his car and the probabilities a

Mr. Clark needs new tires for his car and the probabilities are 0.17, 0.22, 0.08, 0.29, 0.21, and 0.03, respectively, that he will buy Uniroyal tires, Goodyear tires, Michelin tires, General tires, Goodrich tires, or Seiberling tires. FInd the probabilities that he will buy

(a) Goodyear or Goodrich tires;

(b) Uniroyal, General, or Goodyear tires;

(c) Michelin or Seiberling tires;

(d) Goodyear, General, Goodrich, or Seiberling tires.

Solution

a)

Probability will be 0.22 + 0.21 = 0.43

b)

P = 0.17 + 0.21 + 0.29 =0.67

c)

P= 0.08 + 0.03 = 0.11

d)

P = 0.22 + 0.29 + 0.21 + 0.03 = 0.75

Mr. Clark needs new tires for his car and the probabilities are 0.17, 0.22, 0.08, 0.29, 0.21, and 0.03, respectively, that he will buy Uniroyal tires, Goodyear

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