Show work to receive credit 1 At 2273 K the equilibrium cons

Show work to receive credit!


1. At 2273 K the equilibrium constant for the reaction

What would be the equilibrium concentration of N2 if the initial concentration of NO was 0.1339 M?



2. What would Qc be if the pressure of the container increased by a factor of 4.147 for the following reaction?

at 1400oC

2 NO(g) « N2(g) + O2(g)
KC = 2400

Solution

1.

N2 + O2 --> 2NO, Kc = 2400


Kc = 2400 = [NO]^2 / [N2][O2]

NOÂ º = 0.1339M

Kc = (0.1339-2x)^2 / x^2

solve

[N2] = x M

2.

Kp = Kc(RT)^(delta n)
For (RT)^(delta n), which I assume I solve normally, I just plug in numbers for it so I get,
(RT)^(delta n) = (0.0821)(1673)^(2)

So, the only thing I need to compare is Kc and Kp.
pressure is increasing by 4.147, so
I multiply Kc by 4.147
Kp = ((4.147)(0.07520))((0.0821)(353)^(2))

Show work to receive credit! 1. At 2273 K the equilibrium constant for the reaction What would be the equilibrium concentration of N2 if the initial concentrati

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