Consider a triangle A B C like the one below Suppose that A

Consider a triangle A B C like the one below. Suppose that A = 83 degree, B = 40 degree, and b = 70. (The figure is not drawn to scale.) Solve the triangle. Round your answers to the nearest tenth. If there is more than one solution, use the button labeled \"or\".

Solution

A = 83
B = 40
So, C = 180 - 83 - 40
C = 57 degrees

Now, using sine rule :
b/sinB = c/sinC

70/sin40 = c/sin57

csin40 = 70sin57

c = 70sin(57) / sin(40)

c = 91.3

And now,
a/sinA = b/sinB to find a

a/sin83 = 70/sin40

a = 70sin(83)/sin(40)

a = 108.1

So, answers :
C = 57
a = 108.1
c = 91.3