Form a polynomial whose real zeros and degree are given Zero
Solution
Solution:
Given real zeroes -1,0,9 and degree is = 3
Hence f(x) = (x+1)(x-0)(x-9)
=> (x+1)(x)(x-9)
=> (x²+x)(x-9)
=> x^3 + x²-9x²-9x
=> x^3 -8x^2 -9x

Solution:
Given real zeroes -1,0,9 and degree is = 3
Hence f(x) = (x+1)(x-0)(x-9)
=> (x+1)(x)(x-9)
=> (x²+x)(x-9)
=> x^3 + x²-9x²-9x
=> x^3 -8x^2 -9x
