Find all solutions of the equation in the interval 0 2pi 2 s

Find all solutions of the equation in the interval [0, 2pi). 2 sin theta - 1 = 0 Write your answer in radians in terms of pi. If there is more than one solution, separate them with commas.

Solution

2sin(t) - 1= 0

sin(t) = 1/2

We know that sin is positive in quadrants 1 and 2...

sint = 1/2 has principal solution pi/6

2nd quad angle = pi - referenceangle
= pi - pi/6
= 5pi/6

So, nswers :
pi/6 , 5pi/6