The perimeter of a rectangular room is 208 feet Find the len

Solution

Given perimeter of a rectangular room is 208 feet.

Need to find the length and width of the room.

Let the length is L feet and width is W feet.

Given  the length is 2 feet longer than twice the width.

L = 2W + 2

Perimeter = 208 feet.

2(L + W) = 208

L+W = 104

2W + 2 + W = 104

3W = 104 -2 =102

W = 34 feet.

Length (L) = 2W + 2

= 2(34) + 2

= 68 + 2

= 70 feet.

Therefore, Length (L) = 70feet and Width(W) = 34feet