Find the quadratic function y ax2 bx c whose graph passes

Find the quadratic function y = ax^2 + bx + c whose graph passes through the given points. (-1, -7), (1, -1), (2, 14) y =

y=ax^2 + bx + c

points are (-1,-7),(1,-1),(2,14)

Plugging the points in the equation, we get

-7=a -b+c , -1=a +b+c, 14=4a +2b+c

From these three equations, we get

a=4, b=3, c=-8

Therefore the required equation is y=4x^2 +3x-8