6 7 9 5 Given an activitys optimistic most likely and pessim
       6
        7
        9
        5
| Given an activity\'s optimistic, most likely, and pessimistic time estimates of 2, 5, and 14 days respectively, compute the PERT expected activity time for this activity. (Points : 1) | 
Solution
Given that,
optimistic (O) = 2
most likely (M) = 5
pessimistic (P) = 14
The PERT expected activity time for this activity is,
(P+ 4M + O)/6
(14 + 4*5 + 2) / 6 = 6
First option is correct.

