Calculate the standard free energy of formation of 2 mol of

Solution

Ag(s) + Cl2 -------> 2AgCl;;;;;; Standard free energy = (Delta H - T*Delta S);;;;; Standard free energy = [(2*(delta G AgCl2) - (Delta G Cl2) - 2(Delta G Ag)];;;;;;; Standard free energy = [2*(-127070-298*96.2) - (0 - 298*222.96) - 2(0 - 298*42.55)];;;; Standard free energy = -219673.32 J/mol = -219.673Kj/mol