Schving for a reactant using a chemical equation and acetic
Solution
 Ethanol + Oxygen ------> water + Acetic acid
C2H5OH + O2 -----> H2O + CH3COOH
1 mole of Ethanol produces 1 mole of CH3COOH
1 * 46 g of ethanol produces 1*60 g of acetic acid
6.79 g of ethanol produces 60/46*6.79 g of acetic acid
= 8.8565 g of acetic acid.
= 8.86 g (for 3 significants)
Strong acid : When it is dissolved in water it produces H+ ions
Strong Base : when it is dissolved in water it produces OH- ions
HF + H2O <-------> H3O+ + F-
The given species when HF soluble in water are H3O+, F-, HF, H2O so the given compound is weak acid and ionic species are H3O+ and F-
molecular species are H2O and HF
Ba(OH)2 + H2O ------> Ba+2 + OH-
The given species when Ba(OH)2 soluble in water are Ba+2, -OH, H2O so the given compound is Strong base and ionic species are Ba2+ and OH-
molecular species are H2O
HNO3 + H2O -------> H3O+ + NO3-
The given species when HNO3 soluble in water are H3O+, NO3-, H2O so the given compound is strong acid and ionic species are H3O+ and NO3-
molecular species are H2O
KNO3 + H2O ------> K+ + NO3-
The given species when KNO3 soluble in water are K+, NO3-, H2O so the given compound is a salt of strong acid and strong base and ionic species are K+ and NO3-
molecular species are H2O

