Process Burst Priority P1 8 4 P2 6 1 P3 1 2 P4 9 2 P5 3 3 Us

Process

Burst

Priority

P1

8

4

P2

6

1

P3

1

2

P4

9

2

P5

3

3

Using the above data:

Find the Avg Wait time , Avg Turnaround, Avg Response Time using:

FCFS

SJF

Non preemptive priority

Preemptive Priority

Round Robin(Quantum of 1)

Process

Burst

Priority

P1

8

4

P2

6

1

P3

1

2

P4

9

2

P5

3

3

Solution

FCFS

P1--- > P2--- >P3--- >P4--- >P5

0--->8-->14-->15--->24-->27

Average Waiting Time

=(0+8+14+15+24)/5

=61/5

=12.2 milliseconds

Turnaround Time = Burst Time + Waiting Time

Process             Turnaround Time

P1                       8+0=8

P2                       6+8=14

P3                       1+14=15

P4 9+15=24

P5 3+24=27

Average Turnaround Time

=(8+14+15+24+27)/5

=88/5

17.6 milliseconds

Process Burst Priority P1 8 4 P2 6 1 P3 1 2 P4 9 2 P5 3 3 Using the above data: Find the Avg Wait time , Avg Turnaround, Avg Response Time using: FCFS SJF Non p
Process Burst Priority P1 8 4 P2 6 1 P3 1 2 P4 9 2 P5 3 3 Using the above data: Find the Avg Wait time , Avg Turnaround, Avg Response Time using: FCFS SJF Non p

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