Calculate the molality of a solution containing 230g glucose

Calculate the molality of a solution containing 230g glucose (C6H12O6) dissolved in 1.04L of water. (Assume a density of 1.00 g/mL for water.)

Express the answer with the unit (m)

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Solution

moles of glucose= 230/180= 1.28 moles

mass of solvent= 1.04x 1x1000=1040 g= 1.04kg

molality= no. of moles/ mass of solvent in kg= 1.28/1.04=1.23 m