To produce 100 kg of solid aluminum from molten Al2O3 how ma

To produce 1.00 kg of solid aluminum from molten Al2?O3?, how many hours must 5.00 amps be passed through the Al2?O3??

Given that 1.00 kg of solid Al or 1000 g

n = Moles = amount in g / molar mass = 1000 g / 27 g/ mole

= 37.04 moles

Al³⁺ + 3e -----> Al

z = 3 ( no of moles of electrons)

I = current

F = 96485 C mol^-1

n = ( I t / F) * ( 1/z)

37.04 =( 5 * t / 96485) * ( 1/3)

t = 37.04 *96485 *3/5

= 2144111.111 seconds

= 35735.18519 min

=595.59 hours

= 596 hours