Solve the system of linear equations by elimination If there

Solve the system of linear equations by elimination. If there are an infinite number of solutions, enter IS in each answer field. If there are no solutions, enter NS in each answer field. StartLayout 1st Row 1st Column 3 x plus y 2nd Column equals 3rd Column 5 2nd Row 1st Column 3 x minus y 2nd Column equals 3rd Column negative 5 3rd Row 1st Column 2nd Column 3rd Column EndLayout

Solution

From the description available, it appears that the first two of the given system of linear equations are as under. The 3^rd equation, if any, cannot be determined:

3x +y = 5 …(1)

3x- y = -5 …(2)

On subtracting the 2^nd equation from the 1^st equation, we get 3x+y -3x+y = 5-(-5) or, 2y = 10 so that y =10/2 = 5.Now, on substituting this value of y in the 1^st equation, we get 3x +5 = 5 or, 3x = 5-5 = 0 so that x = 0.Hence the solution is x = 0 and y = 5.