A bacteria population starts with 400 bacteria and grows at

A bacteria population starts with 400 bacteria and grows at a rate of r(t) = (450.268)e^1.12567t bacteria per hour. how many bacteria will there be after 3 hours ?

given expression of growth translates into :

if the number of bacteria is represented by n

and the time ( in hours ) by t

then (dn/dt)=450.268 e ^ 1.12567t

=> dn = 450.268 e ^ 1.12567t dt

=>integral dn from 400 to N = integral (450.268 e ^ 1.12567t dt ) from 0 to 3

N-400=11313.233≈11313

=>N=400+11313=117313

A bacteria population starts with 400 bacteria and grows at a rate of r(t) = (450.268)e^1.12567t bacteria per hour. how many bacteria will there be after 3 hour

A bacteria population starts with 400 bacteria and grows at

Solution

Get Help Now

Submit a Take Down Notice